Does the book have an error in the addition of these two vectors?

In summary, the conversation discusses finding a unit vector in the direction of ##-\vec M - 2\vec N##, which is calculated to be ##0.923\hat a_x+0.355\hat a_y+0.142\hat a_z##. However, the book gives a slightly different answer of ##0.92\hat a_x+0.36\hat a_y+0.4\hat a_z##, which may be a typo.
  • #1
CaliforniaRoll88
35
6
Homework Statement
Given the vectors ##\vec M = -10\hat a_x+4\hat a_y-8\hat a_z## and ##\vec N = 8\hat a_x+7\hat a_y-2\hat a_z## , find: (a) a unit vector in the direction of ##-\vec M - 2\vec N##
Relevant Equations
##\hat a_B=\frac {\vec B} {\sqrt {B^2_x+B^2_y +B^2_z}}##
(a)
$$\vec A = -\vec M+2\vec N=26\hat a_x+10\hat a_y+4\hat a_z$$
Unit Vector Formula
$$\hat a_A=\frac{26\hat a_x+10\hat a_y+4\hat a_z}{\sqrt {26^2+10^2+4^2}}$$
$$0.923\hat a_x+0.355\hat a_y+0.142\hat a_z$$
The book gives ##0.92\hat a_x+0.36\hat a_y+0.4\hat a_z##
Not sure how the book get 0.4 for the z-component. Maybe it's an error.
 
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  • #2
CaliforniaRoll88 said:
Homework Statement: Given the vectors ##\vec M = -10\hat a_x+4\hat a_y-8\hat a_z## and ##\vec N = 8\hat a_x+7\hat a_y-2\hat a_z## , find: (a) a unit vector in the direction of ##-\vec M - 2\vec N##
CaliforniaRoll88 said:
$$\vec A = -\vec M+2\vec N=26\hat a_x+10\hat a_y+4\hat a_z$$
I assume that the latter is correct (plus sign, not minus, in front of ##2N##).
CaliforniaRoll88 said:
$$0.923\hat a_x+0.355\hat a_y+0.142\hat a_z$$
The book gives ##0.92\hat a_x+0.36\hat a_y+0.4\hat a_z##
Not sure how the book get 0.4 for the z-component. Maybe it's an error.
Considering that the answer is given with two significant figures and that ##0.4## only has one, this looks like a typo (missing 1).
 
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Likes CaliforniaRoll88 and PeroK
  • #3
Much appreciated.
 

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