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morbello
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what are the eigen values for
k^2-8k+-12=0
i got (k-2) (k+3) as eigen values
k^2-8k+-12=0
i got (k-2) (k+3) as eigen values
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morbello said:what are the eigen values for
k^2-8k+-12=0
i got (k-2) (k+3) as eigen values
morbello said:k^2-8k+-12=0
Eigenvalues are values that satisfy the equation Ax = λx, where A is a square matrix, x is a non-zero vector, and λ is a scalar. In the equation k^2-8k+-12=0, the eigenvalues are the roots of the equation, which are (k-2) and (k+3).
To find the eigenvalues for the equation k^2-8k+-12=0, you can use the quadratic formula or factor the equation to get (k-2)(k+3)=0. This will give you the eigenvalues of k=2 and k=-3.
The eigenvalues represent the solutions to the characteristic equation of the system of linear equations. They provide information about the behavior of the system and can help determine stability and equilibrium points.
No, the equation k^2-8k+-12=0 is a quadratic equation, meaning it can only have two eigenvalues. This is because the equation has a degree of two, and the number of eigenvalues is equal to the degree of the equation.
Eigenvalues have many applications in fields such as physics, engineering, and computer science. They can be used to analyze systems and predict their behavior, as well as to solve differential equations and optimize processes. For example, eigenvalues are used in quantum mechanics to determine the energy levels of a system and in image processing to compress data.