- #1
Soumalya
- 183
- 2
I was going through "Engineering Thermodynamics" by Cengel & Boles studying exergy analysis of a closed(non flow) system.Referring to the attachment as you can see the equation,
δWHE=δQ(1-T0/T)=δQ-T0/T.δQ
should give δQ=δWHE+T0dS (using dS=δQ/T)
but in the textbook it's given as,
δQ=δWHE-T0dS
Any thoughts on it?
δWHE=δQ(1-T0/T)=δQ-T0/T.δQ
should give δQ=δWHE+T0dS (using dS=δQ/T)
but in the textbook it's given as,
δQ=δWHE-T0dS
Any thoughts on it?