How does ${X}_{w}\subset {X^*}_{w}$ occur in modular metric space?

In summary, the inclusion is quite intuitive. To prove it you could do the following. In stead of proving: $x \in X_w \Rightarrow x \in X_w^{*}$ you prove $x \notin X_w^{*} \Rightarrow x \notin X_w$. It will be straightforward then.
  • #1
ozkan12
149
0
Let $d$ be a metric on $X$. Fix ${x}_{0}\in X$. Let ${d}_{\lambda}\left(x,y\right)=\frac{1}\lambda{}\left| x-y \right|$ and The two sets

${X}_{w}={X}_{w}\left({x}_{0}\right)=\left\{x\in X:{d}_{\lambda}\left(x,{x}_{0}\right)\to0\left( as \lambda\to\infty\right) \right \}$

and

${X^*}_{w}={X^*}_{w}\left({x}_{0}\right)=\left\{x\in X:\exists\lambda=\lambda\left(x\right)>0 such that {d}_{w}\left(x,{{x}_{0}}\right)<\infty\right\}$

Then, it is clear that ${X}_{w}\subset{X^*}_{w}$...How this happens ? Please can you explain ? Thank you for your attention...Best wishes...
 
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  • #2
Well, in fact the inclusion is quite intuitive. To prove it you could do the following. In stead of proving: $x \in X_w \Rightarrow x \in X_w^{*}$ you prove $x \notin X_w^{*} \Rightarrow x \notin X_w$. It will be straightforward then. Do you see?
 
  • #3
Dear Siron,

First of all, thank you for your attention...But I couldn't prove this...Best wishes..
 
  • #4
ozkan12 said:
Let $d$ be a metric on $X$. Fix ${x}_{0}\in X$. Let ${d}_{\lambda}\left(x,y\right)=\frac{1}\lambda{}\left| x-y \right|$
What is $|x-y|$? Is it the case that $X\subseteq\Bbb R$?

ozkan12 said:
${X}_{w}={X}_{w}\left({x}_{0}\right)=\left\{x\in X:{d}_{\lambda}\left(x,{x}_{0}\right)\to0\left( as \lambda\to\infty\right) \right \}$
Doesn't this mean that $X_w=X$ since it is always the case that $\frac{1}{\lambda}d(x,y)\to 0$ as $\lambda\to\infty$?

ozkan12 said:
${X^*}_{w}={X^*}_{w}\left({x}_{0}\right)=\left\{x\in X:\exists\lambda=\lambda\left(x\right)>0 such that {d}_{w}\left(x,{{x}_{0}}\right)<\infty\right\}$
What is $d_w$?
 
  • #5
$X\subseteq R$ and ${d}_{w}$ is wrong, I wrote wrong it, it must be ${d}_{\lambda}$
 
  • #6
ozkan12 said:
$X\subseteq R$
Then why do you write, "Let $d$ be a metric on $X$" and never use $d$ afterwards?

I believe both $X_w$ and $X_w^*$ are equal to $X$. For $X_w^*$ and $x\in X$, take $\lambda=1$; then $d_\lambda(x,x_0)=|x-x_0|<\infty$, so $x\in X_w^*$.
 
  • #7
No paper '''arXiv:1112.5561v1.pdf...''' this link, there is something related to modular metric space...And in page 6 you will see definition 2.2...Please can you explain that how happened ${X}_{w}\subset {X^*}_{w}$ ? Thank you for your attention...Best wishes...
 

Related to How does ${X}_{w}\subset {X^*}_{w}$ occur in modular metric space?

1. What is the purpose of a metric function in relation to sets?

A metric function is used to measure the distance between elements in a set. It assigns a numerical value to the distance between any two elements in the set, allowing for precise comparisons and analysis.

2. How is a metric function defined?

A metric function is defined as a function that maps pairs of elements in a set to a non-negative real number. It must satisfy certain properties, such as the distance between any two elements being greater than or equal to 0, and the triangle inequality.

3. Can a metric function be applied to any type of set?

Yes, a metric function can be applied to any set, regardless of the type of elements in the set. It is a general mathematical concept that can be used in various fields, including geometry, topology, and analysis.

4. How is the concept of a metric function related to the concept of a metric space?

A metric function is used to define a metric space, which is a set with a metric function. The metric function provides a way to measure the distance between elements in the set, allowing the set to have a geometric structure.

5. What are some examples of metric functions and metric spaces?

Some examples of metric functions and metric spaces include Euclidean distance in geometry, Hamming distance in coding theory, and Manhattan distance in urban planning. Any set with a defined metric function can be considered a metric space.

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