How does the h cancel out?Shyan said:It does! Its equal to mgh which is a function of h!
It doesn't. ## E_k=\frac 1 2 m v^2 ## is the definition of kinetic energy of a particle with mass m and speed v regardless of what forces are applied to it. Any particle with mass m and speed v, has the kinetic energy ## E_k ##. Now if this particle acquired its kinetic energy by falling from a height h under constant gravitational acceleration g, then the numerical value of ## mgh ## and ## \frac 1 2 m v^2 ## will be equal which means the speed of the particle is ## v=\sqrt{2gh} ##.bay said:How does the h cancel out?
The kinetic energy of an object in free fall is the energy that it possesses due to its motion. It is defined as the energy that an object has because of its mass and velocity.
The formula for calculating kinetic energy is KE = 1/2 * m * v^2, where KE is kinetic energy, m is the mass of the object, and v is the velocity of the object.
Yes, the kinetic energy of an object in free fall changes as it falls. This is because its velocity is constantly changing due to the force of gravity.
The height of an object in free fall does not affect its kinetic energy. The object's kinetic energy is determined by its mass and velocity, not its height.
In free fall, as an object's potential energy decreases due to gravity pulling it towards the ground, its kinetic energy increases. At the point of impact, all of the potential energy is converted into kinetic energy.