- #1
davidhansson
- 8
- 0
Hello, I'm studying machanics of materials.. I'm at the chapter that handles the angle of twist in shafts. There's one exercise that I get the most part of, but there's just a tiny part of it that I don't get!
here's the exercise: http://davidhansson.deviantart.com/art/Wp-20131015-001-407472489
and here's the solution from the book: http://davidhansson.deviantart.com/art/Wp-20131015-005-407472644
what I don't get, is what internal torque really means and how it become (1/2)*25x*x ,,
Where does the "(1/2)" comes from, and where does the extra x comes from..
My intuition is that it should be integrated like: 1/((pi/2)*75*10^9) ∫(15000/0.6)*x integration from 0 to 0.6 ,, which would be the twist in radians for the part AB.
I apologies if it's hard to understand
lot's of thanks/ David Hansson
here's the exercise: http://davidhansson.deviantart.com/art/Wp-20131015-001-407472489
and here's the solution from the book: http://davidhansson.deviantart.com/art/Wp-20131015-005-407472644
what I don't get, is what internal torque really means and how it become (1/2)*25x*x ,,
Where does the "(1/2)" comes from, and where does the extra x comes from..
My intuition is that it should be integrated like: 1/((pi/2)*75*10^9) ∫(15000/0.6)*x integration from 0 to 0.6 ,, which would be the twist in radians for the part AB.
I apologies if it's hard to understand
lot's of thanks/ David Hansson