Percentage of external B field absorbed by inductor?

In summary, the conversation is discussing the calculation of the amount of attenuation and decrease in strength of a magnetic field caused by an inductor placed halfway between a magnetic field source and a measuring point. The question is whether the field is absorbed by the inductor and how to calculate the amount of absorption. The conversation suggests using a numerical analysis software package, such as ANSYS, to figure this out. The person asking for help may be eligible for a low-cost version of the software if they are a full-time student.
  • #1
NotASmurf
150
2
Hey all, if a magnetic field source is at A and an inductor is at B halfway from C, the measuring point will the field be attenuated and decrease in strength due to a percentage of it being absorbed by a solenoid if so how would one calculate the amount, I found how to calculate energy in an inductor E = 0.5 LI^2 from integrating power equation but not any information on my specific problem. Any help appreciated,
 
  • #3
NotASmurf said:
Hey all, if a magnetic field source is at A and an inductor is at B halfway from C, the measuring point will the field be attenuated and decrease in strength due to a percentage of it being absorbed by a solenoid if so how would one calculate the amount, I found how to calculate energy in an inductor E = 0.5 LI^2 from integrating power equation but not any information on my specific problem. Any help appreciated,

A diagram would help.

If you want to figure out how the B-field is deflected by the presence of a piece of ferrous metal (the inductor core), then the way you figure that out is with a numerical analysis software package like ANSYS or similar software. Does that make sense? Are you a student at a university? You may be eligible to use a low-cost version of that type of software if you are a full-time student...
 

Related to Percentage of external B field absorbed by inductor?

1. What does the percentage of external B field absorbed by an inductor represent?

The percentage of external B field absorbed by an inductor represents the amount of the magnetic field produced by an external source that is captured and stored by the inductor. This is also known as the inductor's "magnetic coupling" with the external source.

2. How is the percentage of external B field absorbed by an inductor calculated?

The percentage of external B field absorbed by an inductor is calculated by dividing the energy stored in the inductor by the energy of the external magnetic field. This can also be expressed as the ratio of the inductance of the inductor to the total inductance of the circuit.

3. What factors affect the percentage of external B field absorbed by an inductor?

The percentage of external B field absorbed by an inductor is affected by the inductance of the inductor, the frequency of the external magnetic field, and the physical distance between the inductor and the external source. Additionally, the type of material used in the inductor can also impact its ability to absorb the external B field.

4. How does the percentage of external B field absorbed by an inductor affect circuit performance?

The percentage of external B field absorbed by an inductor can impact the performance of a circuit in various ways. For example, a higher percentage of absorption can lead to a decrease in the overall efficiency of the circuit. On the other hand, a lower percentage of absorption can result in a weaker magnetic coupling and reduced energy transfer between the inductor and the external source.

5. Can the percentage of external B field absorbed by an inductor be increased?

Yes, the percentage of external B field absorbed by an inductor can be increased by adjusting the physical distance between the inductor and the external source, using materials with higher permeability for the inductor, or by increasing the frequency of the external magnetic field. Additionally, incorporating multiple inductors in a circuit can also increase the overall percentage of absorption.

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