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Femme_physics
Gold Member
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I just had arguments with my teacher about my test answer in class. I'm a little upset, but maybe I'm acting like a spoilt brat (I'll be the first to admit it) I went out and I'm using a hallway computer in my college so I can't post images. I still disagree with him-- But I'll try to explain it as best as I can.
Say I have a PNP transistor. I have a source of 6 volts. I have an unkown resistor RE, and a currect Ie = 1.2 mA. I am also told that VBE = -0.7 volts. VBE is connected to the ground.
THE FOLLOWIG IS A DRAWING OF ONLY THE LEFT SIDE OF THE CIRCUIT6 volts ----/\/\/\/\/\-------(EMITTER--->BASE)----GROUND
(the jagged lines describe the resistor RE)
Consider the right side of it (with the collector) irrelevent. Both me and my teacher did.
So, in the solution, can I just do:
Sum of all voltages= 6 - ReIe - 0.7 = 0
5.3 = 0.0012 x Re
Re = 4416.6 ohmsBUT my teacher say I should write VBE in plus in my equation! That since it's been defined as -0.7 volts, it's a mistake to write it in minus in the equationBut that doesn't make sense to me. Vbe is supposedly an electrical component, not a voltage source. There must be a voltage drop there, it can't act as a votlage source!
Please help me see the light!PS If anyone could tell me with explanation who is wrong and who is right (his explanation that it can act as a voltage source is weird to me!) he should still be in class in the next 2 hours...otherwise I'll talk to him next week
Say I have a PNP transistor. I have a source of 6 volts. I have an unkown resistor RE, and a currect Ie = 1.2 mA. I am also told that VBE = -0.7 volts. VBE is connected to the ground.
THE FOLLOWIG IS A DRAWING OF ONLY THE LEFT SIDE OF THE CIRCUIT6 volts ----/\/\/\/\/\-------(EMITTER--->BASE)----GROUND
(the jagged lines describe the resistor RE)
Consider the right side of it (with the collector) irrelevent. Both me and my teacher did.
So, in the solution, can I just do:
Sum of all voltages= 6 - ReIe - 0.7 = 0
5.3 = 0.0012 x Re
Re = 4416.6 ohmsBUT my teacher say I should write VBE in plus in my equation! That since it's been defined as -0.7 volts, it's a mistake to write it in minus in the equationBut that doesn't make sense to me. Vbe is supposedly an electrical component, not a voltage source. There must be a voltage drop there, it can't act as a votlage source!
Please help me see the light!PS If anyone could tell me with explanation who is wrong and who is right (his explanation that it can act as a voltage source is weird to me!) he should still be in class in the next 2 hours...otherwise I'll talk to him next week
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