Why Does Methane Absorb Light Below 274nm If It Photodissociates?

  • Thread starter Aditya Rao
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In summary, methane absorbs light below 274nm because it undergoes photodissociation, a process where the molecule breaks apart into smaller fragments upon absorption of high energy light. This is due to the high bond energy of the carbon-hydrogen bonds in methane, causing them to require a higher energy input in order to break apart. This results in methane being able to absorb light at shorter wavelengths, leading to its photodissociation at higher energies.
  • #1
Aditya Rao
Hello everyone, I am Aditya. I have just begun my graduate studies at the Hebrew University of Jerusalem. I work on Photochemistry. I hope to connect with more people in PF and learn new things! :)
 
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  • #2
Aditya Rao said:
Hello everyone, I am Aditya. I have just begun my graduate studies at the Hebrew University of Jerusalem. I work on Photochemistry. I hope to connect with more people in PF and learn new things! :)
Welcome to PF!
 
  • #3
HI Aditya:I would like to ask you and the forum a question about atmospheric photodissociation using methane as an example.Methane, CH4, has a photodissociation energy of 439 kJ/mole at 298oK, meaning thatCH4 + hv = CH3 + H , hv<274nmIt also has an “absorption cross section” envelope that starts at ~170nm and increases at lower wavelengths.My puzzlement is as follows:

1) If the CH4 molecule is decomposed at <274nm, why does it have an absorption profile (absorb light) at lower wavelengths (the molecule should no longer be intact, correct?)?

2) If the absorption profile has some kinetic function, why doesn’t the profile start near 274nm?I know that the questions are rooted in my ignorance, but could you please help enlighten me. Thank you in advance.

EMH121
 

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