Applying Bayes.
Thank you for the advice! I shall try it.
What did you exactly mean by:
"you will have difficulty usually coming up with numbers for all of the required terms"
?
Proof
Yes the proof was pretty simple:
p(a1 and a2 and... and an)
= p(an | a1 and a2 and... and an-1). p(a1 and a2 and... and an-1).
= p(an | a1 and a2 and... and an-1). p(an-1 | a1 and a2 and... and an-2).p(a1 and a2 and... and an-2).
:smile:
Ciao all,
Is there a generic algorithm to compile the probability P(A)
of any propositional formula A (provided that we have only the probability of each atoms constituting A)?
For example, we have that A= a1 and not (a2 and a3 and ( not a4 and not a5 and not a6 ..) , or any other...
Ciao all,
I have a conjunction of n non-independant hypothesis:
h1 and h2 and ... and hn.
I want to calculate the probability of such conjunction. To do so, I used the product rule p(h1 and h2) =p(h1).p(h2|h1)
p(h1 and h2 and ... and hn) = p(h1).p(h2|h1).p(h3|h1 and h2 )...
Do you...