Recent content by Bacle

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    Is the Closure of a Totally Bounded Set Also Totally Bounded?

    Sazanda: The definition you gave is the same as that of totally-bounded. I mean, totally.
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    How to change e-mail registered in PF

    Hi, All: How do I change the e-mail to which replies/followups were previously sent to me?
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    Is the Closure of a Totally Bounded Set Also Totally Bounded?

    What is your definition ofS being precompact? The one I knew is that the closure of S is compact.
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    Real Analysis: show sequences have the same limit if |Xn-Yn| approaches 0

    nyr: Assume for a moment that the difference xn-yn is always positive, or nonnegative. What can you then say about Limn→∞|xn-yn|? Consider then all other possible cases re the difference xn-yn
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    Where am I going wrong on implicit differentation?

    Haven't looked at it carefully, but slope should be -1.5, after substitution.
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    International Student - chances of getting accepted?

    Fluidistic: Just thought I'd give DreamLord something to think about in case of being accepted to both an Ivy with low funding and a non-Ivy with higher funding. Is the extra $'000's of debt seriously worth the Ivy degree? Still, like I said, if you get good funding for an Ivy, go for it...
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    International Student - chances of getting accepted?

    I'm not sure, but if it is any consolation, according to the book "Higher Education?", those who graduate (at least in undergraduate) from an Ivy-League school , or some other top-10, do not, on average, do better down the road, after, say, 10 years, than those with a degree from a state...
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    Linear Algebra: Kernel and Image question

    So, to be more specific: Let L be the linear map L:R3→R3represented by M, with : M=[ 0 1 0] [ 0 0 1] [ 0 0 0] Then the kernel of M is the subspace spanned by {(x,0,0)}, i.e., if we have the standard xyz-axes, then the entire line is crushed to 0. Now, M2= [ 0 0 1] [ 0...
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    Why the circle can't be homeomorphic to a real interval

    But there cannot be a continuous surjection , because the circle is compact, and the interval [0,1) is not, so f(S1)=[a,b], since the compact subsets of the real line are the closed+bounded intervals, and f continuous maps compact to compact.
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    Medical Nutrition: Is Freshness Worth the Price Difference?

    Thanks, that was helpful. From what I remember, there are no comments in the label re adding nutrients, nor changing anything, but I'll check next time.
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    Linear Algebra: Kernel and Image question

    Tazz01: I may be missing something, maybe even something obvious, but I think that given _any_ linear transformation L from R3 to R3, we can find a decomposition as in i), but it is not true for _every map_ L as above that kerL=KerL2. As example, take a linear map L , whose matrix...
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    Need help understanding these true/false questions

    BTW, ignore my previous post; I misread the OP, sorry. Re #1: No, read carefully: F'(1) is the rate of change of the rain _at t=1_
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    Rather easy problem involving set multiplication

    But what's confusing is that the set {1,1,2,5} is the same as {1,2,5}, by basic set properties. One way of understanding the product of a set by an interval is by considering a subset of the product of 2 intervals, say , the interval [1,5], and [1,2] , then {1,2,5}x [1,2] will just...
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    Linear Algebra: Kernel and Image question

    If T is a linear transformation, T(a+b)=T(a)+T(b), and 0=0+0... Still, unless I am missing something in your notation or otherwise, I think there are counterexamples: For any T:R3→ R3, we have the decomposition in i) by, say, choosing a basis for R3, and representing T using a...
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    Need help understanding these true/false questions

    How can F'(2) be smaller than F'(1)?
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