Recent content by BathroomUser

Makes sense. I guess I wasn't thinking clearly. Thank you so much for the help though!

A new problem has arisen when I use the r value I find to plug into other power loss formulas, ie P=VI and P=V^2/R the answer are different. Attempts: P=VI I=V/R P=60(60/(10+2)) P=V^2/r =60^2/2

Thank you so much! I enjoy that you are not exactly spoon feeding me the answer but instead going through the logistics of the concepts! I will apply those and come back if a problem arises

But the thing is that we have r+10 and r+4 equating to our resistance, so couldn't it be the r be the same number though?

The voltage drop across the internal would be the same as we're using the same source and the only difference is the external resistor

Homework Statement A battery with an emf of 60 V and an internal resistance (r) is connected to a 10 ohm external resistance. The power lost inside the battery is 50w. The same battery is then connected to a 4.0 ohm resistance. The power loss is 200w. What is the internal resistance of the...