Recent content by bd24

hmmm, so now i have the speed of the ball in the vertical, is it possible to use trig to solve for the horizontal speed? like 2.54/sin(3°) = 48.5 ms? ps. thanks for all the help

ok, i tried again and now have a value of 0.365N for the combined pull of the sun and the moon. hope this is the right answer..

Homework Statement a tennis player standing 12.3 m from the net hits the ball at 3° above the horizontal. to clear the net the ball must rise at least 0.33m. if the ball just clears the net at the apex of its trajectory, how fast was the ball moving when it left the racket? my answer was...

so net force on person standing on the Earth's surface during a solar eclipse is equal to (the force of the moons gravity upon the person + the force of the suns gravity upon the person) subtract the force of the Earth's gravity upon the person, which is given as 600N. Is this correct?

Homework Statement at a moment of total eclipse the moon lies in a straight line from the Earth to the sun. If your normal weight is 600N how much is your weight decreased by the combined pull of the sun and moon? [b]2. Homework Equations Mass of sun - 2.0x10^30 kg distance from...