Recent content by Biochemgirl2002

i don't know what to do, but i am not asking help for the whole thing i am just wondering what it means by mean weight differs from 20g? from 1.5g-41.5g? or does it mean when the weight is not 20g

a) since np has to be greater than 5, n*p= 50*.5 =25 so yes, we can use this since it is much larger than 5. now, for mean, i believe the equation is saying that the mean is np, which is 25 but in this equation we do not have a q value, so this is where my issue begins... what should i use...

Yes, sorry. I am not sure that i have done the right steps. Mainly my issue is because the question says X~N(20,25) and i am not sure if i am to assume that the mean is 20 and the standard deviation squared is 25. as well, my other concern is that the equation isn't the standard deviation...

a) P(X<18) = (18-20)/sqrt25 =-2/5 =-0.4 then you use the standard normal table and find that; P(X<18)=0.3446 b) P(X>27) = (27-20)/5 = 7/5 = 1.4 P(Z>1.4) =P(Z<-1.4) =0.0808 C) =(13<X<23) =13-20/5 , 23-20/5 =-7/5 , 3/5 =-1.4 , 0.6 P(Z<0.6)-P(Z<-1.4) =0.7257-0.0808 =0.6449

the Buchner funnel is used often in the lab, but i was wondering if there was a great enough transfer loss in the filter paper to switch to an alternate funnel for filtering by suction. I've looked into sintered glass funnels but i don't know if it would have the same transfer loss since the...

thank you so much for taking time out of your day to help me out! i appreciate it

alright, the p is different than any variable I've used in this course, is p always going to be 0.76? and k is reducing from 20 until 2?

On the table you provided me with, (the first link) the answer i got was correct with Probability of k successes or more. but i don't know if that is the right since it is asking the backwards answer for this question, since more than 2 did NOT use google, its tripping me up.

oh! alright so the answer should be P(V^c ∩ D) / (P(D)) =0.375/0.4 =0.9375 Is this correct?

i believe that the solution is to do 1- (less than 2 did use google) so it would look like 1- ((20!/0!20!)0.76^0*0.24^20 + (20!/1!19!)0.76^1*0.24^19 + (20!/2!18!)0.76^2*0.24^18) = 0.99 but logically, this does not make sense to be .99. what am i doing wrong?

i think i believe that it means only the intercept between a and b which i found out was actually zero if there is no intercept then they are mutually exclusive, now that i know this . i am still having trouble understanding if they are independant i found this website...

A) (0.5)-(0.3) =0.2 b) c) i have no clue how to determine from just a set of numbers if they are independant or mutually exclusive

A vaccine has a 90% probability of preventing a certain disease. The probability of getting this disease if a person is not vaccinated is 50%. In a certain region, 25% of people get vaccinated against this disease. Find the probability that a randomly selected person from this region A. has the...

Alright, so if i did the equation (49*48*47*46*45*44)/(6*5*4*3*2*1) , so therefore the answer would be 13,983,816 ?

Question: When playing Lotto 649, you must pick six numbers from the numbers 1, 2, …, 49. In how many ways can you do this? My attempt n!/r!(n-r)! = 49!/6!(49-6)! (49x48x47x46x...x1)/(6x5x4x3x2x1)(43x42x41x40x...x1) =0.06 . (edit: i redid the question and just made it (49x48x47x46x45x44)/(6!)...