It's being stretched 4 feet beyond its natural length of 2 feet, so the natural length is the 0 and then 4 feet beyond that is 4.
At first I had 2 to 6, but then I realized that that meant stretching it from 2 feet beyond its natural length to 6 feet beyond it because the limits refer to change...
I fixed my previous post before you had posted, I thought... sorry!
I don't know... I read it as stretching it from 2 to 5 feet beyond its natural length...
Homework Statement
The amount of WORK to stretch a spring 4 feet beyond its natural length of 2 feet is 10 ft-lbs. Find the work required to stretch the spring from 4 feet to 7 feet.
Homework Equations
W=\int^{b}_{a}Fdx=\int^{b}_{a}kxdx=[kx^{2}/2]^{b}_{a}
The Attempt at a Solution...
Homework Statement
The amount of WORK to stretch a spring 4 feet beyond its natural length of 2 feet is 10 ft-lbs. Find the work required to stretch the spring from 4 feet to 7 feet.
Homework Equations
W=\int^{b}_{a}Fdx=\int^{b}_{a}kxdx=[kx^{2}/2]^{b}_{a}
The Attempt at a Solution...
Homework Statement
What is the value of xln(x)-x when x=0?Homework Equations
I'm assuming you do L'Hopital'sThe Attempt at a Solution
I'm assuming you factor out the x, leaving:
x(ln(x)-1)
but that's still not in the form of \frac{\infty}{\infty} or \frac{0}{0}
Would you do...