Recent content by BMcC

Okay, so I have the total circuit current and all of the individual resistances and the battery's voltage. I'm a little confused on where to go from here to be honest!

Homework Statement Consider the circuit shown in the diagram below, for R1 = 5 Ω, R2 = 8 Ω, R3 = 8 Ω, R4 = 8 Ω, and V0 = 8.0 V. Calculate the current through R4. Homework Equations Loop rule: The sum of all potential changes around a closed loop is zero Junction rule...

Ah wow how silly of me. That changes everything. Thanks TSny!

Homework Statement A copper bar with a cross sectional area of 4.40 cm2 and a length of 0.62 m has one end at 1 °C and the other end at 97 °C. Find the heat flow through the bar if the thermal conductivity of copper is 385 W/(m·K) Homework Equations R = (λ*L)/A I = ΔT / R k = 1/λ...

I was just going under what the question gave me in terms of q2 and q3's charges. They are both negative charges, therefor wouldn't the Force come out negative just in terms of signage? I suppose this is where I'm confused about the question.

Not quite sure I understand what you mean by - sign indicating that the force acts towards the other charge. Care to explain a little further?

Three charged particles are placed at the corners of an equilateral triangle of side L = 1.74 m. The charges are q1 = 3.63 µC, q2 = −8.05 µC, and q3 = −6.31 µC. Calculate the magnitude and direction (counterclockwise from the positive x axis) of the net force on q1 due to the other two...

The graph shows a snapshot of a traveling harmonic wave; eight points are indicated. Answer the five questions by selecting from the choices below a) ← b) → c) ↑ d) ↓ e) The velocity is zero 1.If the wave is moving to the right, what is the direction of the velocity of the particle...

I was doing this example from my textbook and looked at the solution guide. I'm confused as to where the textbook got a certain number. In the numerator of their work, they got (1)(6)(2), which I'm assuming is the width of the skinny rectangle, the total length of the bottom section...

Oh, nevermind. I see what you meant. I was supposed to add the m*r^2 to the original spoke moment of inertia. Thanks for your help!

So I used the wrong formula for the moment of inertia for the spokes because I chose the wrong axis Spokes 1/12 10kg*0.88m2 = 0.6453 kg*m2 Since there are 5 spokes, 0.6453*5 = 3.227 kg*m2 My two rings haven't changed, so now it'd be: 3.227 kg*m2 + 78.42 kg*m2 + 0.778 kg*m2 =...

Okay so I'd use this formula to get the moment of inertia for the 5 spokes. Then once I have that, is my parallel axis work at the bottom correct?

Hmm, I'm still confused.

M*l2/12?

The outer ring of the wheel has a mass of 51 kg, the inner ring, 6 kg, and each spoke, 10 kg. Find the mass moment of inertia of the wheel about an axis through A and perpendicular to the page. Assume r1 = 124 cm, r2 = 36 cm. Each spoke is 88 cm long. DIAGRAM What I've learned in...