True. I was using the moment of inertia about one end of the stick, which is indeed (1/3)mL2. In my case i guess the D was still the distance from the old axis to the new axis. In using the moment of inertia about the CM, and making d the distance between the pivot and the CM, I was able to...
Homework Statement
A very light, rigid rod with a length of 0.570 m extends straight out from one end of a meter stick. The stick is suspended from a pivot at the far end of the rod and is set into oscillation. Determine the period of oscillation.
Homework Equations
omega =...
I've been being confused lately as to the 2 methods. The example I'm thinking of is when a weight of mass m is hung on a spring and it stretches x meters.
First of all, I know you can equate the spring force (kx) to the force of gravity (mg), to get
k = mg/x
But is it also possible to...