hi dears,
sorry for late reply acctualy I was out of city
as per your instructions I had put the area as a A
and I find out these total reluctance 24.3 A(area)AT/wb
magnetising force H = 40.81*10^2 AT/m
F = .5020 A(area) AT/wb
now to find out the flux or resistance...
hi dear,
sory for late reply I was out of city as per your quidence I had put the area as A
now I have
total reluctance 24.3 A(area) AT/wb
H = 40.81 * 1o^2 AT/m
F = .5020 A(area) AT/m
now if I go to fine the E.M.F as per your guidence
i have this formula...
hi dears but how can we put 2 unknown in a same equation for example for reluctance we need area S= l/ mu * A.
and same for flux weber= NI / l/munot *mur*A
Hi dear,,
how are you kindly help me the equation you tell me to drive for reluctance in this the area is not given and I have not know equation to drive it kidly help
hi dears,
kindly tell me the complete procedre to find out the v1 and v2
v1= -145/8
v2 = 5/2
I have tried it and I reach here
Apply Source transformation theorem.The 5A and 3ohms &2 ohms are converted into single voltage source 25V ( 5A*3+2) in series with 5ohms(3+2).But the positive...
an iron ring of mean length 5 cma has an air gap of 1mm and a winding of 200 turns. If the permeability of iron is 300 when 1A current flows through the coil find the flux density.
its answer is 94.2 mWb/m^3
kindly help how I would drive it