Recent content by Crazy Old Coot

Greetings, I am almost 70 years old now, and have retired from formal employment. This was no my decision, but Company policy. I've been making stuff since I was knee-high to a grasshopper. Not everything worked out first time... I love hydraulics, and structures with triangulation. I have built...

Thank you, guys, for your replies. I appreciate the time you took.

Well, it now remains for me to acquire the gearbox that I have been offered and set up the geometry of rollers as per my rudimentary spreadsheet, and see how the real world compares to the numbers. I can play with sprockets to get the real driving torque because speed is not an issue.

Ha ha... a palaeontologist might be more appropriate!:oldsurprised:

Thank you for your contribution. I wasn't even considering the speed with which the first deformation takes place. That is a separate system to the driving system. However, as the material is fed into the rollers, it is akin to many continuous small manual advances and re-deforming. (I.e...

Thank you for this. It's a heck of a lot of maths for my old brain to process, but I'll try.

Thank you, Lnewqban, for your reply. Your answer actually highlights the crux of the matter! Consider that, once the "simply supported beam" has failed, further deformation is merely a question of displacement of the centre roller, with hardly any additional force. So, under a deformation that...

In principle, the ring is, at any instant, a beam being loaded in the centre, and in a failing state. Thus, to drive the material continuously through the rollers, Force x Velocity = Work done/time = power. 60.P/2.pi.N = T The units pan out, but is the concept correct? The faster the work is...