Recent content by dainceptionman_02

would pushing an object and gaining an acceleration from Newton's third law be considered an external force then? consider the normal force. on a free body diagram, the object experiences a gravitational force from the earth and a normal force from the surface. the normal force from the surface...

In the physics text for F(net) = ma, the text expresses how "F(net) must be the vector sum of all the forces that act on the body, and that only forces that act on that body are to be included in the vector sum, not forces acting on other bodies that might be involved in the given situation."...

upper division as a 300+ level course meant for juniors. Another Modern Physics is part of the 3rd sequence of Engineering physics for freshman/sophmores is a pre-requisite. Some Modern Physics books could be an off-shoot of this, but im looking for pure Modern Physics designed for juniors as...

i recently bought books for (self study) Mathematical Methods of Physics, Thermal Physics, Classical Mechanics, and Introduction to Electrodynamics. I should probably get an upper division Modern Physics book before going to Quantum Mechanics (Griffiths). What is a good/usual Modern Physics...

ok, so usually one of the first equations in Diff Eq is F = -kx, which is the second order differential equation mx'' = -kx, where they give you the only general solution in the universe as Acoswt + Bsinwt. I was wondering, why can't you just separate the equation and get m∫x''/x = -∫kt'' which...

but Halliday still wrote it in the way that i showed in the original post...

this formula is missing the cosine of the angle in one dimension

i'm copying from the book... Hookes Law - F = -kx W = Fdcos∅ since ∅ is 180°, W = -Fd = -Fx W = ∫(-Fxdx) now the book says, from Hookes Law equation "the force magnitude F is kx. Thus, substitution leads to W = ∫(-kxdx)" why are they saying to substitute the magnitude of the force and not the...

lol, well it does get stuck in the ground. it is a volcano launching a rock that "lands" at the base of the mountain.

the final velocity is zero in the x and y-direction for this particular situation. shouldn't that equation work?

the answer to this question uses the above formula with the tangent function and solves for the initial velocity, i used the equation (v.sinθ^2) = (v.sinθ)^2 - 2gΔy, setting final velocity equal to zero and solving for initial velocity. this kinematic equation gives a different answer. can...

forgive me, i don't have an instructor to beat this answer into me

so on Earth, the viewers would have to set a wait time at 2.3 years for this to finish?

i have just started on relativity, so be simple. you are going to travel 1 lightyear at half the speed of light. therefore, it would take 2 years to travel 1 lightyear. on Earth, you would see me going half the speed of light, so it should take two years as well? i calculated gamma as being...

whoops, i just noticed the question states a region, but not in a conducting loop or geometry.