Recent content by dimsun

I am not really helped by the answers. The only remark that is a bit helpfull is Lavinia Zhentil, U(2) is not SU(2). So I don't need any clarification about SU(2). Is there someone else that can clearify U(2)?

Roger Penrose wrote in "The Road to Reality" that the symmetry to describe the weak force is the "group SU(2) x U(1) or more correctly, U(2)". (page 641) And "The group might be expressed as SU(2) x U(1)/Z2, where the '/Z2' means 'factor out by a Z2 subgroup'. However, there is more than one...

Mass belongs to the gravitomagnetic system while the other charges, like electric charge, weak charge and color charge do not. Mass generates gravity, so what do you mean? Is it better to say that the higgs boson generates the masses of the vector bosons? Or can you explain what you mean...

The graviton (spin 2) and the Higgs boson (spin 0) are both involved in gravity. The Higgs carrying mass, and the graviton carrying the gravitational interaction. On the internet I red that a lot of people wonder if there is a connection. In electroweak interaction the forces are carried by...

Thanks Bill, but there is a difference. In SI-units we have mass m, and this has a different dimension then m\sqrt{G}. Likewise in SI-units we have electric charge q, and this has a different dimension then q\sqrt{K}. In SI-units mass m and electric charge q don't have the same dimension...

For SU(2) the three represented gauge fields are A_\mu^1, A_\mu^2 and A_\mu^3 and for U(1) the gauge field is B_\mu. The A_\mu^3 and B_\mu are electrically neutral. The photon \gamma and Z particle are combinations of these. My interest is the dimensions of the following parameters...

I am interested in using hypercomplex numbers and not using tensors. Therefore a question about the difference between spinors and vectors. I read that they both can be written as quaternions. Vector: Vq = ix + jy + kz Spinor: Sq = ix + jy + kz So what is the difference between...

Agreed. That is only true when the two vectors are zero. In the situation you showed q = p = 0 Dimsun

Yes, I do not understand the concept of rest-mass and rest-energy. rest-energy is used in the following expression: E_0 = \sqrt{E_{rel}^2 - p_x^2c^2 - p_y^2c^2 - p_z^2c^2} How could this energy be rest energy when the 3-momentum is not zero? And how could rest mass be incorporated into...

Rasalhaque, I was not using natural units, I just forgot adding c to momentum. You are right, equations must be dimensional correct. With vector quantities I mean both the 3-momentum is zero and vector quantity \frac{m_{rel}v^2}{c^2} is zero. Restmass: m_0 = \sqrt{\frac{E_{rel}^2}{c^4} -...

The equation m_0c^2 = \sqrt{E_r^2 - p_x^2 - p_y^2 - p_z^2} is a bit misleading. It is more appropriate to write it as: E_0 = \sqrt{E_r^2 - p_x^2 - p_y^2 - p_z^2} This is the same as E_r = \gamma E_0 In case the vector quantities are zero we have the following two equivalences: E_r =...

Before I thought about relativistic mass I already believed in a vector quantity with dimension \frac{m}{v} next to mass. I had different reasons for that. First reason In quantity tables I noticed that vector quantities and scalar quantities alternate. "Time is said to have only one...

How stupid of me, I checked it and overlooked it. But it doesn't undermine my line of reasoning.

You are right, you didn't say that. At high school, I didn't understand why momentum was a different quantity then mass. Momentum was mv, so it was mass according to me. But photon's have momentum but don't have mass. So momentum is a quantity on it's own. Now I make difference between all...

I am not laughing. It is pity that you say something like that. I want to discuss with logical reasoning not with personal statements. No one is forcing you to discuss this subject with me. You didn't convince me with your reasoning. That's all. I never heard that relativistic mass is...