Recent content by drewbagel423

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    Equation for dissipation of a capacitor

    ok so my calc is a little rusty, but here goes: (using V_{in}(t) = At) RC\frac{dv_{c}}{dt} + v_{c} = At integrating both sides with respect to t (not sure about this part) RCv_{c} + v_{c}t = \frac{At^{2}}{2}+constant solving for v_{c} v_{c}(RC+t) = \frac{At^{2}}{2}+constant...
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    Equation for dissipation of a capacitor

    No this is something I'm having trouble with at work I think I have an understanding but I'm having a problem putting it all together KVL says the sum of the voltage in a loop is equal to zero. \sum V_{loop} = 0 so if the input voltage is a function of time V(t) = -3t the...
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    Equation for dissipation of a capacitor

    yes, i do remember doing that, basically adding up all the nodes, right?
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    Equation for dissipation of a capacitor

    sorry, you're talking to an ME, have no idea what the KVL equation is
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    Equation for dissipation of a capacitor

    i'm not trying to get the cap's voltage to drop linearly, I'm saying what if the voltage into the cap drops linearly with time, how do this change the formula you posted? for instance, in the formula you gave, Vo @ t=0 is 30, V1 @ t=1s is 27, V2 @ t=2s is 24, etc
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    Can Previous Results Estimate Box Response When Plate Cools Faster?

    Let's say I have a box, mounted to a plate in a vacuum (pure conduction). The system is initially at a steady state at temperature Ti. The plate then begins cooling at a rate of 3 C/min. The box is going to cool at some rate, and with some time constant. For this test, I have place a...
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    Equation for dissipation of a capacitor

    Hi, I'm trying to evaluation the voltage of an RC circuit as it is dissipating a stored charge. Actually trying to do this under two different situations. The first is let's say the circuit has reached steady state for a given input voltage, Vo. Now I reduce the voltage instantly to some...
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