Recent content by DrNG

Thanks for your reply! I get it now. Can you please suggest on which lines should I attempt further.. I'm not so comfy with rotating frames...

My line of thinking is as follows: \omega_{PQ} = \frac{v_{\perp}}{\ell} = \frac v\ell \frac{\sqrt3}{2} Similarly for rod ##QR## \omega_{QR} = \frac{v_{\perp}}{\ell} = \frac v\ell \frac{\sqrt3}{2} Is my reasoning correct?