Hi Neil
Sorry will do that in the future.
Yeah usually the ref is 0 degrees agreed.
But in this question the line voltage is not given but the phase voltage Vao.
So given that information I have tried to work it out.
Also the line voltage leads the phase voltage by 30 degrees.
Could be wrong
A 50 Hz ac three phase supply has a peak voltage of 100 V. Calculate the instantaneous voltage of each phase at a time of 7.5 ms.
Looked all over google and can't seem to find an equation for this?
Can anyone point me in the right direction?
The phase angles are given here because it is a worked example. Questions there after do not give you these angles, instead they say for example use Vab for reference.
Yes but just by looking at the diagram you must be able to tell which is which?
Using Vab as a reference, the reference is always 0 degrees.
So if Vxy is used as a reference in another question that will also be 0 degrees.
How do I find out the other two?
Ib= (-12.4-j6.88)-(9.57-j6.38)
Ib= -12.4-j6.88-9.57+j6.38
Ib=(-22-j0.5)A
Why does the -j6.38 become +j6.38?
Ia=(9.57-j6.38)-(0.454+j13)
Ia= 9.57-j6.38-0.454-j13
Why does the +J13 become -J13?
Thanks
http://i60.tinypic.com/nmntpj.jpg
How do you differ what angle for example Vab, Vbc, and Vca are?
I notice the reference angle is always 0 degrees but how can you tell for the other two?
Thanks in advance.