Recent content by fredro

Exactly as I concluded. To say again, these problems are entirely unrealistic and it can be confusing since I have a background in electronics as a technician. I find this class frustrating at best. My instructor also tried to argue that a current source in series with a capacitor would not...

If you click on the picture with the circuits, all the information is there. The meter circuit, the circuit with i0 and the instructions. I would gladly explain, but it will be far easier for you just to look at the attached picture. If you can't read some of the values, let me know.

I agree. I said parallel because in the circuit, they are in parallel. With the switches in the circuit, there exists a moment of time when they are the only two elements in the circuit.

Have you redrawn the circuit? I know, without incertitude, the circuit reduces to an equivialent circuit that has just the 1Ω meter element and a single resistor of value R/2. I don't care about the six resistors on the end because I know they don't pass current. I am merely asking for...

No. They design these "circuits" with the intent to trick you into wasting time analyzing it. They have even gone as far as stating as much. You see, my ECE dept. is more concerned with tricks than knowing if we can actually solve circuits. It's a major point of contention with the faculty...

The attempt is not really relevant. This is from a past quiz; it is not a current assignment. I'll try to explain myself again. The meter circuit can be reduced to an equivalent circuit that is the movement with a resistor in parallel. This resistor has a value of R/2. If you want this...

The circuit is below. This is from a quiz from earlier this semester. The equivalent circuit for the meter reduces to the D'Arsonval movement in parallel with a resistor who's value is R/2. I know that no matter what current you want to measure, R must be greater than or equal to 18Ω so that...

I don't know if this is the right place to post this question, but here goes. Whilst solving a circuit in class from a homework assignment, we arrived at a situation where a capacitor was in parallel with just a single independent DC current source. The question is, would current flow...

Here's what I have so far. Unfortunately, I keep running into nonsensical, trivial answers where my systems keep having coefficients of zero. :confused: I've spent several hours on this problem.

Here's what I have so far. Unfortunately, I keep running into nonsensical, trivial answers where my systems keep having coefficients of zero. :confused: I've spent several hours on this problem.

Homework Statement I am asked to solve for vX, PDEV BY iS1, P ABS BY vS3 (please see attached figure). We have only covered KCL, KVL, Ohm's law and Power in class. No Thevinen theorem, so it can't be used to help solve. The Attempt at a Solution I know that current will...

I think I can help. First thing you need to realize is that for each leg of a parallel circuit, the emf (or difference of potential) across any leg is going to be the same (14V in this case). This means you can "isolate" resistors R4 and R5 and just look at that one leg. So you know that 14...