Recent content by galimax

Thanks Klungo, I get it now. I did not differentiate the left side in line 2 properly with respect to x. Just to document the solution: Instead of: y = log(b) x. b^y = x, dy/dx * b^y = 1, dy/dx * x = 1, dy/dx = 1/x. it should be: y = log(b) x. b^y = x, dy/dx * b^y * lnb = 1, dy/dx * x * lnb...

I found this proof on a website for the derivative of ln x: y = ln x. e^y = x, dy/dx * e^y = 1, dy/dx * x = 1, dy/dx = 1/x. My question is, why can't we use a similar method to prove the derivative of log(b)x = 1/x, like this: y = log(b) x. b^y = x, dy/dx * b^y = 1, dy/dx * x =...