so are you saying that this is simply a definition? I'm sorry but I still can't seem to understand it...so the average power based on this definition, then, is merely an approximation of the "real mean"?
I am slightly confused by the definition of average power if the power function $p(t)$ is sinusoidal. Why is it that only one period is considered?
I mean I know that it simplifies calculations but if we assume that the period of $p(t)$ is $T$ and I compute the average power over...
Hi hallsofivy, sorry I didnt quite understand your reply.
And oh, it's 5/27 not 5/9. Perhaps a better way of explaining it to me would be how to identify the coefficients a_k such that \frac{5}{27} = \sum \frac{a_k}{3^k} ?
Hi guys, I'd like to ask about ternary expansions. they seem easy but I'm having a hard time doing this as well as searching for tips online, specifically for x \in [0,1].
I know that ternary expansions are similar to decimal expansions but for example, how do you find the ternary expansion of...
Hi guys,
I was reading about random walks and i encountered one step of a proof which i don't know how to derive in a mathematically rigorous way.
the problem is in the attached file and S is a random walk with X_i as increments, X_i =
{-1,+1}
I know that intuitively we can switch the...
Hi guys, let's say I have a transformation T from (p,q) to (u,v). The inverse transformation would be T^{-1} from (u,v) to (p,q)
Now, J(T) = u_{p}v_{q} - u_{q}v_{p}. On the other hand, J(T^{-1})= p_{u}q_v - p_{v}q_{u}. But |J(T)J(T^{-1})| = 0 and not equal to 1. I know it's supposed to be 1...
Hmm, this is the hint given:
"Parametrize the curve first using polar coordinates. Next, find the period which is to be done in Cartersian coordinates."
you see, the equation i gave above is the curve for the line integral of \int |y| ds.
hi tiny-tim, I'm stuck. for one, r can't be 0 as the formula I'm dealing with has r=22. i just typed it as r as a generalization.
well,for cos 2\theta = 1, a solution, for example would be theta = 0 or theta = \pi. that would just be a line in the polar axis.