Recent content by Johfb

Thanks for you explanation gneill :smile: The period of rotation of the planet is the same as the Earth i.e. T=86400s. So that's how I managed to do it :smile:

I see.. :wink: I thought that if E<0 then it was a closed elliptical orbit and that when E=E_{min} then it was a closed circular orbit.. so I was expecting to get E_{min} which would be small but positive. I'm a tad confused. I couldn't see where my method or calculations were incorrect, so...

Homework Statement Calculate the energy of a 100kg satellite associated with a geostationary orbit around a planet. Homework Equations Kepler's 3rd Law: T^{2} = \left( \frac{4 \pi^{2}}{GM_{p}} \right)r^{3} Velocity equation: v = \sqrt{\frac{GM_{p}}{r}} Planet mass: M_{p}...