Hi Sammy and thank you for the help, unfortunately, the way you solved it is a bit over my head as I've never used natural logs or anything at that level. Is there any other way you could solve it maybe? Thank you again!
I've been working on this question a bit and I decided that
f(x)=30 - 20((0.80)^x)cos(2πx)+3sin(2πx) is a better representative of this question however now I am wondering how to graph cos(2pix) + 3sin(2pix) anyone have some tips for me?? It's the 2pi that's throwing me off. Thank you
A point on the outside of the axle of a truck has a circular motion that can be modeled by a sine curve. If you measure the distance from the axle's centre to the bottom of the truck, that distance remains constant as long as the truck is on a level piece of road. If the truck goes over a bump...
Hmm I'll have to study the Distributive Law more then I guess I'm not familiar enough with it and I know it's very important thank you again, I really appreciate the help!
Oh my goodness! That works! That's it ahhhh I'm so happy thank you! :)
One more thing though so that I know for the future, how did you rearrange the (k+1)*x from the original x + kx?? Thank you again!
Alright so I redid the equation and expanded it to
1 = -x² + kx + x – k and then set it to zero like I was taught to do.
0 = -x² + x + kx – k – 1
But now I have too many values to find the discriminant in which there should only be a, b and c as I'm sure you already know, thank you for...
I don't expect anyone to do it for me, I just didn't remember the method to convert the fraction believe me I know the only way to learn is to do it yourself, I just got stuck on this part of the problem. Thank you though, I appreciate the help.
I think you're on to something I mean that method is the only way I know how to solve this problem and I must have messed up my FOILing like you said, but to be honest I don't know how to correct it, could you or someone please let me know? I wasn't sure what to do with the 1/(x-1).
Thank you
Find the equation of the line with slope -1 that is tangent to the curve y = 1/(x-1).
The equation of a line with slope -1 is y = -x + k
The curve is y = 1/(x-1)
Set the y-values to each other: 1/(x-1) = -x + k
Rearrange and set equal to 0:
1 = -x² + x + k
x² - x + 1 – k = 0...