Recent content by kirito

second equation $$amplitude(\omega_{drive})=\frac{\frac{force _{drive}}{m}}{4*\pi^2*\sqrt{\frac{tao*\omega_{drive}}{2}^2+\omega_{natural}^2 +\omega_{drive}^2}$$ this for getting the amplitude as a function of frequency we actually used it to find the value of the force on each mass

the equations I used $$x=a*sin(\omega *t +\phi)+c$$ after enough time for getting the movement of every wave , the amplitude was gotten through the graphs by checking the peaks average in the stable condition

as for the whole experiment ,we were studying the behaviour of oscillatory systems subjected to an external force and observing the link between the frequency of the applied force and the amplitude of the system, as well as what maximizes it. We start out our experiment by selecting two...

hi I actually also wondered where is this more appropriately placed , we had to do an experiment regarding simple harmonic motion and write a report about it but this part was extra I just added it from my own violation since I was interested in checking if the results, I will get align with...

should I be expecting a higher amplitude at resonance for a mass that's heavier to an extent form another where each is attached to a spring vertically , I assumed that's true since the heavier mass will stretch the spring more meaning when moving like a sin or cos wave the amplitude...

this was really informative thank you for the patience

I understood the first part (great visualisation helped a lot ), I just can't seem to imagine hanging my whole weight from the pipe (as in how )

I think what confuses me is the mass being hallow on the inside. When the bar is in contact with the upper part of the mass, it applies a force upwards. However, when it touches the lower part, it applies a force downwards. Wouldn't this normal force on the mass be totalled as zero ...

yes, particularly when the masses are on the edge just touching the bar sideways .

that there is no acceleration in the y direction

In the system on the right, we have two masses, labeled as mass 1 and mass 2, connected by a rod and a rope. This setup allows the masses to slide closer when a third mass is pulled down. Initially, the system possesses an angular velocity. for the system on the left, we have a rod with two...

I understand that in the initial condition both the net torque and net force are zero since the system is in a static state , the net torque remains zero as the mass down is being pulled , the two blocks get pulled towards the axis of rotation by a radial force but I am wondering what is...

I read about this for planes but did not know the same concept is applied for sail boats I will read more about this thanks

sorry would you be able to use different terms to explain this , I tried to translate the new words such as two bearings precession, yet it is still a bit hard to digest I appreciate the help

true I did make that assumption , is there any conditions other than the net torque being zero ? since I phrased the same condition differently