Recent content by m0286

Hello I have another question: It says: Evaluate in closed form n(sigma)i=1 (2^i - i^2) (The n is above the sigma and the i=1 is below) what i did so far is: (sigma)2*2^i-1 (sigma)i^2 =(2(2^n -1)/2-1) - (n(n+1)(2n+1)/6) now do I need to do something else to shorten this...

Question is: Evaluate the following limits lim x--> 0 4^x - e^2x / 2x So i take derivatives but that's where I am confused... Whats the derivate of 4^x... x4^-x? and is the derivative of -e^2x -2e^x? So then that leaves me with 4x^-x -2e^x /2which is 0... so do i...

I still don't get it! Ok this could be very wrong, I am just not sure how to do it any other way. (im going to use $ for the integral sign) v(t)=$-t dt =-1/2 t^2 so v(t)=-1/2 t^2 ( and I've changed km/h to m/s) 20m/s=-1/2 t^2 t=sq root( 20/-1/2) t=sq root(40) t= 6.324s...

ooops wrote the question wrong! woopsies wrote the question wrong... its actually ln(4+4y+y^2) so I arranged the inside so (y+2)(y+2) so can I use ln(ab) = lna + lnb so that ln(y+2)(y+2)=ln(y+2)+ln(y+2)? Would that we right? Thanks

hi quick question for this: simplify the following ln(4+4y+4y^2) i know i need to use those simplifying rules for ln which are ln(xy)=lnx+lny ln(1/x)=-lnx ln(x/y)=lnx-lny ln(x^r)=rlnx but for the question I am asked to simplify.. it doesn't really follow any of these... I was wondering...

still confused? Sorry.. this question is driving me crazy:frown: I just can't seem to understand it.. I've been staring at that website, and nothings making sense to me. Do I need to figure out the time first? because by those equations that's whut its looking like... But I can't figure out...

Hi Another question It says: A car is traveling at 72km/hr. At a certain instant its brakes are applied to produce a nonconstant deceleration of s"(t)=-t(in m/s^2) How far does the car travel before coming to rest? Now there's a lot of questions like this in the book, however they use a...

Thanks! ohhhh Makes so much more sense to me now, i got it.. Thanks a lot!

Hello I have a calculus problem (1st year) that I cannot solve I am completely confused: It says: We are given that the Earth's gravitational acceleration is gE=9.8m/s^2 (downward) and that on Mars gM=3.72m's^2 (downward) If a projectile is fired upwards from the Earth it lands back on Earth...

Ok thnx :) I see it was a stupid mistake... I went from =2(sinxcosx)+2(cosx(-sinx)) to =2sinx+2cosx+2cosx-2sinx Because i multiplied them by the 2 infront of the brackets.. guess that's wrong! haha but thanks. I always get confused when you do certain things and dont. Thanks for all your help!

hello! Thanks a lot for the help... I decided to use the product rule since I am most familiar with that. So once I did that I ended up with (sinx)(cosx)+(sinx)(cosx) and (cosx)(-sinx)+(cosx)(-sinx) so you add them together for f'(x)=h'(x)+g'(x) now i ALWAYS mess these big things up... so...

Hello! This is probably real simple, just I am confused the question is Differentiate the following y=sin^2 x - cos^2 x I know you need to use just f'(x)+g'(x) and I know the derivate of sinx is cosx and derivative of cosx is -sinx... but what do you do with the sin^2... is the derivate...

Last Question I Promise! It says given the function (sq root x^2-x)/x-x^2 find the intervals in which it is defined and examine the particular limit. lim x-> 1+ (sq root x^2-x)/x-x^2 Well I found the intervals to be, -infinity<x<0 and 1<x<infinity. So to examine the limit tried plugging in...

Thanks! Ohh ok yea I get it so 1(x-3)+6 is x-3+6 so x+3 then the x+3's cancel out and you get 1/(x-3) which is 1/-6... THANKS!

Hello 1 More Question It says Calculate the following limits: lim x-> -3 ((1/x+3)+6/(x^2-9)) So what i did was changed x^2-9 into (x-3)(x+3) and then made that the common denominator so I got 1(x-3) + 6/(x-3)(x+3) then the (x-3)'s cancel and your left with 6/(x+3) but then I plug int he...