Isn't the fourth derivative of position "acceleration of accelerate" ?
like :
g is the third derivative of position in falling
g = GM / R^2
dg / dt = dg/dR * dR/dt = -2GM/R^3 * V
(vector that points top is + for Velocity)
so g is chanching with dg/dt rate ?
The problem is indeterminate
m = 0
withouth any calculation
because the central star is a Dot Gravital point at it can not create coriolis/euler(i think)
and if there are other stars around it will be indeterminate for sure
Here is the only way that problem will not be...
Aha got it
I assumed we know what :
Acceleration(y) and Acceleration(x)
thats why [theta] was known in my calculation
but if u just told that ay/ax is not known it wouldn't get this long :D
thanks 4 ur time
Sorry for my poor English ... :shy:
here in this pic :
Do you agree that eccentricity is uniqe for a given Velocity(+ vectors) and acceleration (+ vectors) ?
and we can find eccentricity from :
e/Sin[theta] + Cotg[theta] = -Vy/Vx
and we can find w :
V Sin(X) / R
(X was shown...
I just gave an example for circular because it was easier
the Velocity given by Questioner(?) and vectors given must be currect
if not it will fall on the star / run away from star
and the Questioner already mentioned that it is a Ellipse so it is uniqe
look @ page 2 or hallosivy
they...
it is not indeterminate
since Velocity vectors and Acceleration vectors are known
its like saying
at the distance of R and Mass of central star = M , we will have acceleration = K
also at the distance of 2R and Mass of central star = 4M we will have same acceleration = K
but we know...
Hi
as Gravity Force always points to Sun (from Earth to sun) and there is no other force
there will be no acceleration in e[theta]vector (e[theta] vector makes 90 degree with er)
so there will be no coriolis force or Rw' that's why i said all the sentences with e[theta] in it equals to...
oh... Latex errors ... at the end of Velocity that is e\theta not that
Click on the Latex images and read there
and for :
\theta = 180 - A
it was a exception for this picture
it depens on which quarter u want to calculate it may become like 180 + A
http://www.picamatic.com/view/3620071_ellipse/
and w = V Sin X / R
:edited X:
and from Polar Direction we have :
R er
=> derivate (d f(x) / dt i`m not sure about the English word)
Velocity = R' er + Rw e(theta)
=> derivate again for acceleration
R'' er + R'w e\theta+ R'w...
Hi
I have read Bio-Savar , Amper law (also maxwell) about Magnetic fields
but all of them had I
bio-savar :
B = \frac{\mu0}{4\pi
} \frac{ids Sin\theta}{r2}
Amper :
\int B.ds = Iin \mu0
but what about a Electron moving in a line path ? how big will be its magnetic field ? it...