makes a little bit more sense...i was thinking since the (...) part was squared, I had to solve it first... I rememberd that b is what ever makes the (...) = 0 and that was it. Okay...lemme go try and work this problem. It's on mymathlab.com and I hate it! Thanks for the tips...brb...
sorta...i know that when its ex: x^2+4x+8, i know which ones are a, b, and c. But I don't see how you could tell which one was a b and c in that problem. Do I have to solve the problem first?
I think it will be easier on both parts if you can talk me through it.
---------- Post added at 23:09 ---------- Previous post was at 23:07 ----------
the problem is f(x)= -3(x-6)^2-4 I know I have to set it equal to zero. It wants the vertex, y intercept and axis of symmetry. I don't...