Recent content by monahanj09

I think that example confused me. But I understand what's going on now a little bit better. I think n=V(t+τ)=A+Be^(-t+τ/τ) and m=A+Be^(-t/τ), and that setting them over each other and reducing that should come out to e^-1. But it comes out to e, not e^-1. m/n does come out to e^-1 though, so I...

So in that case V(t+τ) = A+Be^(-t+τ/τ). I put that over the equation you gave me for V(t), but I'm not sure what it represents or what it's equivalent to. I assume it's equivalent to one of the ratios it shows in the problem statement, I just can't tell which or how to prove it.

I see that the m line is time τ apart from the n/p line. I also see that m is the difference between A (the maximum possible voltage) at time t and V(t), and that n is the difference between A and V(t+τ), and that p is the difference between m and n. I can't quite tell how to relate them though...

So try setting V(t) equal to V(t+τ), which would be A+Be^(-t/τ)=A+Be^(-t+τ/τ)? That still doesn't relate n, m, and p to each other, though. From looking at the graph, it looks like there's some sort of relationship between m/n/p and A or A+B, but I can't quite tell what it is.

Homework Statement Question is hereHomework Equations Shown in the image, but just to restate: Vc(t) = A+Be^(-t/τ) n/m=e^-1 OR p/m=1-e^-1 The Attempt at a Solution First thing I tried to do was solve the Vc(t) equation for e, which comes out to e=(-A/B)^(-τ/t). I'm not even sure if...

Okay, so after doing some research and going back over my notes, I have a fairly good idea of what's going on. For a non-inverting op amp, as this one is, the gain can be calculated by 1+Rf (a.k.a. the value of the feedback resistor)/Rs (a.k.a. the value of the source resistor). Multiplying...

So you feed it two separate voltages, and it gives you a voltage that is somewhere in between?

Okay, so after doing a little more reading I have a better idea of what's going on. I understand the output voltage is the difference between the input voltage at the non-inverting input (+) and the inverting input (-), multiplied by the gain. In my problem I know the input voltage at the...

It just amplifies a voltage, I think. I know the + and - have to do with if it's inverting vs. non-inverting, but I don't really understand the how/why. Sorry if I'm being difficult, I'm doing my best to understand all this. I've been reading about them in between replies trying to get a feel...

The input voltage from 2.3V source, and I think the current being fed back from the 12k resistor.

Well, from what we've learned from class, I'm inclined to say it's the current that runs through Rth. I'm not exactly sure why though.

The gain isn't specified anywhere. So I'm just going to solve it as I normally would, and treat A as an undefined constant, basically? I've been looking around online to try to get an understanding of what I'm doing and what the OpAmp does, and it's slowly making more sense to me, but I'm...

So will that just be Ri/Rth? And it will be amplifying Ro? Or am I completely off?

Wouldn't that just be 2.3V, or am I misunderstanding you?

Homework Statement For the following circuit, if Rth = 50kΩ, Ri = 1TΩ, and Ro = 50Ω, calculate the output voltage. Do not neglect Rth, Ri, or Ro. Circuit is here. Homework Equations Possibly KCL and/or KVL, possibly the non-inverting op-amp equation Vo=(1=Rf/Rs)Vi, Ohm's Law V=iR...