Recent content by NASSAfellow

Homework Statement I was practicing exams for PHY 1 but I don't understand how to do this question, even with the mark scheme. A cricketer bowls a ball from a height of 2.3m. The ball leaves the hand horizontally with a velocity u. After bouncing once, it passes just over the stumps at...

heat of fusion... joules per mole density of ice... kg per m^3 conductivity for ice W/m K = m kg/s3

In that case: I will try but I don't really know them that well... Density of ice is in ?will find out? Heat of fusion of water is in ?will find out? Conductivity for ice is in ?will find out? Temperature in ?will find out from the web? Kelvin perhaps? x (thickness) is in m

Density of ice is in g/ cm^3 at 0 degrees C Heat of fusion of water is in Calories per gram Conductivity for ice is in W/m/ degrees C Temperature in degrees C x (thickness) is in cm

Okay, here is what I have got LpAdx = kA (change in) T dt / x So sub in values first then rearrange (it is easier that way); 79.72 (latent heat of fusion for ice) x 0.917 (density) x A (Area) x 4.5 (change in x) = 2 (thermal conductivity for ice) x A (Area) x 11 (change in temperature) x...

Help needed urgently

I am lost, please help Cristo!

So does this mean I am lost? Cristo...?

Also the delta sign did not copy for the heat conduction equation dQ/dt = kA (Change in) T/x

Of course! I have seen it now! Sorry, when I pressed copy on the pc it did not copy: dQ= LpA , where p is density of ice!

Wait hang on, just received your msg.. let me do it

I have confused myself with density and difference in etc... Is it this? Where is density? Change in time = Latent heat of fusion*change in x^2 / thermal conductivity of ice * 11

okay... I have got this far... dt=Ldx^2/kT Is this correct?

LA \,dx = \frac{kA \Delta T}{x} dt Someone gave me this^^, but still confused

Yes, I think so, Webassign just gave me the question to do, and the formula to use.