This is what I tried.
Imagine that the two U's were separated and were moving towards each other. Since their final momentum is 0 (they're touching each other in equilibrium as the problem states), their initial momentum ought to be 0 because the system is closed. So, since the tube on the...
Two streams of water flow through two U-shaped tubes (the two U-tubes are facing away from each other, but touching each other at the base of the 'U's). The tube on the left has cross-sectional area A, and the speed of the water flowing through it is v. The tube on the right has cross-sectional...
But,
net force is a constant. It is not proportional to time t.
I also looked at:
power = work/time = force x velocity
power ~ t
force x velocity ~ t
since force is a constant,
velocity ~ t
wouldn't this be right? why sq.root of t?
Homework Statement
A particle starts from rest and is acted on by a net force that does work at a rate that is proportional to the time t. The speed of the particle is proportional to:
sq root of (t)
t
t^2
1/sq root(t)
1/t
Homework Equations
power = work / time...
Homework Statement
A man wishes to pull a crate 15 m across a rough floor by exerting a force of 100 N. The coefficient of kinetic friction is 0.25. For the man to do the least work, the angle between the force and the horizontal should be:
0
14
43
66
76
Homework Equations...