Recent content by Nikhil R

I understand, sincere apologies.

Thank you SammyS. No words to thank you enough. I have been stuck with this little thing for more than 10 hours now and you just gave me the right information to understand it. I hope i have got it right Thank you.

I mean the angle between F and [-dr].

So in this case , is it correct to say that applied force and -dr are in the same direction and hence, cosθ between them is 1.

I intend to use the variable r and express force/ field at a point in terms of r.

Thank you SammyS. But is dr a quantity that is defined by standard. i have always seen it as a quantity that we define for our problem with a liberty to chose the direction according to each problem. Kindly help me correct my mistake.

Thank you SammyS for responding to the question. I really appreciate your help. Could you please help me understand how vector dr is defined. What i believed so far was that dr vector has an infinitely small magnitude and occurs in the direction of the motion that we choose. Therefore, the...

Snigdh thank you for responding. I believe the sign of E.dr should be decided considering the mutual orientation of E and dr. Plus if they are parallel, and minus if they are anti parallel. In this case, the applied force is against the electrostatic force and the displacement is in the same...

Biker, The applied force, i believe should be in the same direction of the displacement. Here, the electrostatic force of repulsion should act away from the point say towards right considering the source charge at the origin and the point at a distance R to the right of it. Hence, an equal...

Thank you again avalanche. I understand this derivation that u just gave me.But what intrigues me is the fact that a very primitive simple basic method of using the integral calculus to find out work done due to a variable force is not giving me the right result. I believe i am missing something...

I get the same sign inverted answer when i try doing the same problem for Gravitational Potential Energy. The work done in bringing a point mass from infinity to a pint R . In this case The applied force is against the attractive gravitational force. F applied is outward and dr is inward, and...

Thank you avalanche. I really understand the point. It definitely means that we should apply the dot product, make sure the cos θ is substituted andthen evaluate the integral. That is where my doubt arises. Using this idea, i try to find out the electrostatic potential at a point R distance...

I have been pondering on the above question for hours now. I must be missing some important basics here. Please kindly help me solve the confusion. I believe that the sign of emerging from evaluation of any physical quantity should imply the physical meaning and vice versa. But this does not...

On applying definite integral to find work done, we integrate F.dx and apply lower and upper limits. Should we apply the dot product, before integration , that is -1 for θ = 180, 1 for θ = 0. Or will the limits applied and their values suffice in deciding the sign of the final value. I have...

Another question i have on this regard is, on applying definite integral to find work done, we integrate F.dx and apply lower and upper limits. Should we apply the dot product, before integration , that is -1 for θ = 180, 1 for θ = 0. Or will the limits applied and their values suffice. I have...