Recent content by oceansoft

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    Convering double intgral to polar coordinates

    Sorry for annoying you like this so the does the integral look this \int^{pi/2}_{0}\int^{\infty}_{0} e^-(rcos^2\theta+rsin^2\theta) r dr d\theta what am i doing wrong?
  2. O

    Convering double intgral to polar coordinates

    No not rly u can say its \sqrt{(x^2+y^2}
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    Convering double intgral to polar coordinates

    sorry for the troble but is this what it looks like then? \int^{pi/2}_{0}\int^{\infty}_{0} e^-(rcos^2\theta + rsin^2\theta) dr d\theta = \int^{pi/2}_{0} 1 d\theta = pi/2
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    Convering double intgral to polar coordinates

    so i get this right \oint^{\infty}_{0}\oint^{\infty}_{0} [SIZE="3"]exp^-(rcos(o)+rsin(o)) dr do is that in polar coordinates now right? and then i just do the ingeral? and is that what i would always do when tranforming to polar? when i did that i get left with \oint^{\infty}_{0}...
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    Convering double intgral to polar coordinates

    Homework Statement Hey am studing for my up coming exam and i am having trouble with transforming double intrgral to polar coordinates i have no idea where to start or anything so can someone explain it to me Homework Equations this is example \oint^{\infty}_{0}\oint^{\infty}_{0}...
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    Finding Local Extrema and Critical Points for f(x,y)=ysin(x)

    Am not too sure what u are asking but if i sub any of the x's i found using sin(x)=0 into cos(x)=0 i will just get 1 or -1 does that mean that y is always equal to zero? therefore x= n pi and y=0 btw thanks for ur time
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    Finding Local Extrema and Critical Points for f(x,y)=ysin(x)

    So u mean like x= 0, pi, 2pi and so on and then subing those x's into 0=ycos and then solving for y? but if i do it will go on forever beause it says to find all critical points
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    Finding Local Extrema and Critical Points for f(x,y)=ysin(x)

    Find and classify all local minima, local maxima and saddle points for the function f(x,y)=ysin(x) i can do this question however i am having problem with finding the x and y intercepts i get fx= ycos(x) and fy=sin(x) 0=ycos(x) and 0=sin(x) i start to have problem now after someone...
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    What is the area of a region in the positive quadrant bounded by three curves?

    Yeh thanks i know where i went wrong when i type 1^4/3 in i didn't put the bracket around 4/3. btw are u such i havn't gone wrong anywhere else if not thanks for the help
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    What is the area of a region in the positive quadrant bounded by three curves?

    Hey thanks for the help but i just miss type that when I was working it out on paper i did use y=(x-1)^3 and that what it is in the question but sill got the wrong answer. do u know what else i might of done wrong?
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    What is the area of a region in the positive quadrant bounded by three curves?

    Hello everyone am new to this forum my name is lucy and i hope i can help and get help from other i got this tutorial question that i seem to keep getting wrong :s i hope someone can help me :) the question is Use a double integral to calculate the area of the region in the positive quadrant...
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