Recent content by Oz123

well, all I can think for as a reason is that they are both dilated by gamma from u, but then the rate at which they tick are the same, so the difference should be the same.

Homework Statement [/B] Homework Equations The rear clock ahead example gives vL/c^2: The Attempt at a Solution I think the solution is the same, because even if there is a time dilation due to u (downward velocity) both clocks would slow down at the same rate and so the time difference...

ya I think I am getting it, thank you. I still am a bit confused, but I guess if we forget about the clocks and just think about the lights, it would work. Thanks a lot :)

Yup, thank you! Noted everything :)

Oh, also if we can think of the rest frame as B, so C is the moving frame with respect to B which is moving the other way, that's where the negative sign goes. Thanks for explaining :)

Ya I think I get now, thanks a lot!

Oh, I think I understand now why there is a negative sign, in non relativistic velocity, Vac=Vbc+Vba...So Vab=Vac-Vbc where Vab is velocity of a with respect to b etc. So in things like this, we need to look at the non relativistic limit if the vector addition makes sense, right? So if that...

Thanks a lot! Ya, I don't know why he used opposite signs, both the trains are going in the same direction, but the velocity addition formula right there is the one derived by Morin. But v1, which is the train A is not at rest on any of the frame besides the train A itself, in the first...

Ok, so here's another example Morin did in his book: Ok, so the thing that confuses me is when he used the velocity addition equation: Note:4c/5 and 3c/5 are their speeds relative to the ground. Where v2 is the velocity of the S' frame, and v1 is the velocity of the object moving in the...

Ya, I seriously don't know. Like if we forget about the lights and just focus on the clocks, or if I just gave the question without Morin's solution. The answers might arrive differently.

hmm, ok the experiment he did is for the light going to each sides at the same time in the S frame. But what if we don't have those lights? Suppose we just use the clocks and use Lorentz transformations only. So using the clocks only, the time difference in S' is 0, but not in S...So we do this...

But why did he used the time difference in the S' frame when it is supposed to be observed in the S frame? Why can't it be Tr-Tf since it is the time difference in the train as observed in the platform?

In his 2nd derivation he states that two events are simultaneous in the ground frame...But in his question, the clocks are simultaneous on the train frame, and the ground frame they are not simultaneous...Is he wrong then?

Here's Morin's derivation for the result. 1st one is the one above, 2nd he used Lorentz transform, but he used the primed frame to get the time delay, which should be zero in that frame but not zero in the unprimed frame...For the unprimed frame, what he should get is the one I did above

But we want the time delay in the S frame, because the question is asking what the time delay is as observed from the platform. The one Morin derived using Lorentz transformation is the same thing in the example, the time delay between the clocks. What he did though is to subtract the time for...