Recent content by peter46464

  1. P

    B Minkowski metric, scalar product, why the minus sign?

    We got there in the end. Thanks ever so much everyone for your patience. This has been bothering me for years, so it's a relief to get it cleared up. Even in MTW's Gravitation and Wald's General Relativity there's no reference to symmetric bilinear forms.
  2. P

    B Minkowski metric, scalar product, why the minus sign?

    So when Schutz talks about the scalar product of two vectors he actually means a symmetric bilinear form (aka the Minkowski metric) acting on those two vectors?
  3. P

    B Minkowski metric, scalar product, why the minus sign?

    martinbn - yes, I saw your post and the definition. I assumed, when you said "what do you get?" that that was a genuine question, ie that you didn't know the answer and were as puzzled as I am. Whoops, please don't take offence! A definition isn't really an answer though, is it? Am I correct in...
  4. P

    B Minkowski metric, scalar product, why the minus sign?

    So, as I understand the answers given here, ##\vec{e}_{0}\cdot\vec{e}_{0}=-1## is not a scalar product but a symmetric bilinear form. And the definition of the metric $$g_{\mu\nu}=\vec{e}_{\mu}\cdot\vec{e}_{\nu}$$involves not scalar products but a bunch of (please excuse the technical language)...
  5. P

    B Minkowski metric, scalar product, why the minus sign?

    In Schutz's A First Course in General Relativity (second edition, page 45, in the context of special relativity) he gives the scalar product of four basis vectors in a frame as follows: $$\vec{e}_{0}\cdot\vec{e}_{0}=-1,$$...
  6. P

    Checking derivation of the curvature tensor

    Homework Statement I am trying to derive the curvature tensor by finding the commutator of two covariant derivatives. I think I've got it, but my head is spinning with Nablas and indices. Would anyone be willing to check my work? Thanks Homework Equations I am trying to derive the curvature...
  7. P

    Why no absolute derivative in this example of geodesic deviation?

    Yep, as far as physics is concerned “basic misunderstanding” is my default position. However, in my defence I would say that to the uninitiated this is a genuinely confusing problem. The cars' separation ##s## is given by $$s=\Delta\phi=d\cos\left(vt\right)=d\sin\theta$$and is calculated...
  8. P

    Why no absolute derivative in this example of geodesic deviation?

    Thanks to all for your help. Who would have thought two cars on a sphere could be so complicated. Can I now assume (a) there's a consensus that Void's "constant curvature" answer...
  9. P

    Why no absolute derivative in this example of geodesic deviation?

    My physics is struggling here, so I'm going to resort to a classic “argument by authority”. My example of geodesic deviation on a sphere is similar to the CalTech Exercise 24.10 here: http://www.pma.caltech.edu/Courses/ph136/yr2004/0424.1.K.pdf The solution (Answer 23.10) is given here...
  10. P

    Why no absolute derivative in this example of geodesic deviation?

    But surely (except at the equator) the distance between the geodesics is not measured along geodesics but along circles of constant \theta. Therefore I can't be using geodesic coordinates?
  11. P

    Why no absolute derivative in this example of geodesic deviation?

    Thanks. I've been away for a few days, but still can't see this. In my example how are the new (normalized) coordinates related to the old (\theta,\phi) coordinates? Also, the original line element is ds{}^{2}=d\theta^{2}+\sin^{2}\theta d\phi^{2}.How would I find the new line element using the...
  12. P

    Why no absolute derivative in this example of geodesic deviation?

    Sorry to labour this, but how do you get from the Christoffel symbols for a unit sphere \Gamma_{\theta\phi}^{\phi}=\Gamma_{\phi\theta}^{\phi}=\frac{\cos\theta}{\mathbf{\mathbf{\sin\theta}}},\Gamma_{\phi\phi}^{\theta}= \sin\theta\cos\theta to Christoffel symbols that vanish? I know that the...
  13. P

    Why no absolute derivative in this example of geodesic deviation?

    Thanks, I need to think about this. I still can't see why the Christoffel symbols vanish along geodesics on the surface of a sphere. Surely the Christoffel symbols will only vanish if we're using a flat metric?
  14. P

    Why no absolute derivative in this example of geodesic deviation?

    What are geodesic normal local coordinates? Are spherical coordinates always geodesic normal local coordinates? I've tried Googling the term, and got something about "applying the exponential map to the tangent space at p". I'm OK with "tangent space" but have no idea what "exponential map" means.
  15. P

    Why no absolute derivative in this example of geodesic deviation?

    Thanks, I've attached a pdf showing the calculation.
Back
Top