Homework Statement
A proton is in a place where the electric potential is V, and as a result it has a potential energy E. If you replace the proton with an alpha particle (twice the charge of the proton and four times the mass) in the same place, it will experience an electric potential...
Ok thanks gneill and berkeman. I guess you guys had said their accelerations were same in the beginning but it definitely helped figuring out why. I''ll talk to my professor tomorrow and I think it's actually due Tuesday so if there's something I'm missing I'll bring it up tomorrow?
Thanks!
So like Acceleration,=? meters/s^2 Q=1.6x10^-19 C, m=1.67x10^-27kg, E=? N/C, F=? Newtons,
a=F/m
F= QxE
a=(QxE)/m
Only problem is there is nothing about direction or velocity
What differs in the problem is their distance maybe, their velocities and their direction. Other than that I assume their acceleration since that's what we are looking for.
So I cheated a bit and googled how to find acceleration from velocity of proton and got this on Yahoo
F = Qvb
(Q- charge of proton = 1.6 x 10 ^-19 C (constant))
(v- velocity of proton) We know their velocities
(b-magnetic field) We know the E is uniform
F=ma We find force from...
F=ma=Q x E?
m(same for all protons) x a(what we need to find) = [ Q(which is same for all protons) x E (which is uniform)]
So we need to find the force
I'm trying to find where it talks about uniform electric fields in my book but they are don't have anything saying "uniform". But I think the equation for force on a charge is F=Q x E
And the only equation I can think of for acceleration and force is F=ma
Ugh yeah my professor likes to give more conceptual questions sometimes so there might not be hard calculations to do but instead just a rule or law I need to be explaining