Keeping(m/L) together, I now got:
V^2*(M/L)=T
and I get 16.39^2/.0533=5042 and that seems too high.
I know I should square v because anything to the 1/2 power = a sq. root...
I found a similar problem online:
A phone cord is 4.20 m long. The cord has a mass of 0.180 kg. A transverse wave pulse is produced by plucking one end of the taut cord. The pulse makes four trips down and back along the cord in 0.745 s. What is the tension in the cord? ___ N
Solution...
I've got another one.
An airplane traveling at v = 154 m/s emits a sound of frequency 5.20 kHz. At what frequency does a stationary listener hear the sound during each of the following times? (Use 344 m/s as the speed of sound.)
1) as the plan approaches (kHz)
2) after it passes (kHz)...
I can't find the equation I used for what's shown above, for some reason.
I did find this one online: v = (T/(m/L))^0.5
and when I re-arranged it to find T, I got v^2(m)(L)=T which, when I plugged in the numbers, came out to .0021, which doesn't seem right.
I don't know what I'm doing...
Question:
A phone cord is 3.75 m long. The cord has a mass of 0.200 kg. A transverse wave pulse is produced by plucking one end of the taut cord. The pulse makes four trips down and back along the cord in 0.915 s. What is the tension in the cord?
Maybe I'm using the wrong formula or my...