Recent content by PoohBah716

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    Can some explain vector a+b must be great than a-b

    Homework Statement Can some explain vector a+b must be great than a-b Homework Equations none this is conceptual The Attempt at a Solution I believe this is false because the direction can be + or -. can you explain to your thoughts
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    W=(1/2)KA^2 Can someone explain this equation in detail & Q

    I know using Hookes law can be used after finding the mass. I want to know more how W=1/2KA^2 is derived in this solution. My understanding is W is the potential energy the and A^2 is the amplitude and the reason it is square because ?
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    W=(1/2)KA^2 Can someone explain this equation in detail & Q

    Homework Statement A mass resting on a horizontal frictionless surface is attached to one end of a spring. 3.6 J to compress spring 0.13 m. released at max acceleration 15 m/s. What is the spring constant and mass I would like to dicuss this question how the equations are derived. can someone...
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    Inelastic and elastic collision (please explain)

    Homework Statement If a object 1 & 2 collide as a perfectly inelastic collision, would they will both stop. Also If this same situation happened elastic? please explain if this is true or false and draw a free body diagram if possible. Homework Equations F=ma Newton second Law KE=1/2ma The...
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    Explain relationship of Kinetic energy and acceleration

    Can someone someone explain and possibly draw a free body Diagram. kinetic energy of an object has the same direction as its acceleration
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    Easy collision question, momentum and energy

    P1=p2 M1(Vf-Vi)=-M2(Vf-Vi) KE1f+KE2f=KE1i+KE2i 1/2M1f+V1f^2+1/2M2fV2f^2=1/2M1iV1i^2+1/2M2V2f^2 Could you walk me through this problem, I am getting stuck.
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    Easy collision question, momentum and energy

    Homework Statement A spring (k=4200N/m) and box A (mA=120kg) are on a frictionless incline, as shown below . Box A is pressed against the spring such that it is compressed 1.0m, and then released. Box A then hits, and sticks to box B, 1.0m farther up the ramp from the uncompressed position of...
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