I am looking for the angle needed to rotate the conic to eliminate the xy-term
but the angle I find is negative and I need the counter-clockwise angle of rotation to satisfy 0 < theta < 90 degrees. Where am I going wrong? Or what else do I need to know? Thank you for your help...
Thanks for your help. Office Shredder. Are either of these possible as polar points
(0,1.249 rad) , (infinity, 1.249 rad)
because I am thinking since r = 0 it cannot possibly be a line like y=3x. Convert the radian angle I found into a polar point that extends infinitely into the I...
I have gotten from this equation: y=3x into its polar form by substituting
x= r cos (theta) and y=r sin (theta) to get me here:
r sin (theta) = 3r cos (theta) Substitute and simplify.
r sin (theta) - 3r cos (theta) = 0 Subtract 3r cos (theta) from both sides...
i guess the solution needs to be modified since they are all multiples of pi/4. There might be a better way to understand this , I solved
3*pi/4 = pi/4 + 2*pi*k for k and got k=1/4. Then plugged this into the general equation for all solutions and got, pi/4+2*pi*1/4 which becomes
pi/4+pi/2...
What is the algebraic method to get from X = (pi)/4 + 2(pi)K into this form => X = (pi)/4 + (pi)/2K ? These are the general equations for all solutions to this original equation: 6 sin^2 X-3=0 , I can understand how to get the general equation graphically can someone show me how to get...