Ken G, I think I understand what you're saying. So we know dQ = 0 because it is a fast process and does not have time to exchange heat (as said by skrat)? And the only thing we can actually calculate is the work done on the surroundings gas? Which is the integral of the constant surrounding...
I think "a sudden explosion" just means the gas expands rapidly and we will ignore any energy needed to create the explosion. So, I should find the work that the volume change does on the constant background pressure?
I'm unsure of how to do this.
Homework Statement
A gas initially occupying a volume V undergoes a sudden explosion, causing its volume to triple to 3V. Assuming that the pressure of the environment (atmospheric pressure po) remains constant, find an expression for the work done by the gas.
Hint: Please notice that an...