Okay, so this makes more sense now. I was in the mindset of Zn when I saw H.
So we have S3 = {(1)(2)(3), (1)(2, 3), (3)(1, 2), (1, 2, 3), (1, 3, 2), (2)(1, 3)}
With H = <(3,2,1)>
Using permutation multiplication to generate H we get:
(3,2,1)^1 = (3,2,1) = (1,3,2)
(3,2,1)^2 = (1,2,3)
(3,2,1)^3...