Recent content by r_prieto5

Hmm ok this just got tougher. What formula did you use for that? Also, why would it get to 160°? I would need it to work at around 50-60° tops. I don't think eddy currents would have such a large effect here to heat it up that much if i use neodymium magnets

How do i select the current? I can't do trial and error as the point of this whole calculation is to buy the right type of coil diameter.

Omg thanks a lot for this. I will get into it later on today if possible and get back if something in unclear, just ote thing, is the distance between magnets included in these formulas?

Ok wow thanks for the sketch and reply. Let's see if I understand though. Why does Fsi result vertically up only and Fsii result horizontally to the right only? Fsi is directly in front of Fmi and Fsii is with Fmi so that both Fs forces are pulling the triangle towards them, therefore balancing...

Hello everyone, So for a personal project I want to calculate the force necessary for a solenoid (electromagnetic coil) to keep a permanent magnet triangle locked diagonally up and down at the same time so that it does not move in any direction. I need to know the values for coil thickness...

Nevermind, I simply could not find the necessary information from the links provided but I managed to find them from some solutions manuals. Here they are in case anybody needs them Chain link pressure N=p⋅d2⋅b2 Resonance frequency ω=πN/cq⋅1/√(N/q+v2=2πƒ)

@Nidum I could not find the equation in any of the three links but I managed to find them elsewhere Pitch Diameter = P ÷ sin (180° ÷ N) Outside Diameter = P × (0.6 + cot ( 180° ÷ N) ) Regarding the surface pressure on the chain link, would you have any diagrams or formulae I could use...

Homework Statement Power=P, rotation speed n1, rotation speed n2, chain center distance c, life = Lh All I need for this one is the formula for sprocket diameter. I have found calculators (https://www.rbracing-rsr.com/calcsprocketdiam.html) but no reference to the formula. Chain pitch and...

Ok, I think I have now found the safety factor against sliding with sum of resisting moments/sum of driving moments = (moment on shaft face + moment by contact pressure)/torque Now for the yielding safety factor i found the formula FS=yield strength (of the shaft i guess)/von mises maximum...

@Nidum It seems the links you give me don't have much information on the actual values asked and if they do, they require that I already have calculated some of the other variables (i.e. the calculator). Do you have any information on how I should start the approach?

@Nidum Thank you, I am pretty busy at the moment but I will get more into it next week and let you know if it works!

Homework Statement https://drive.google.com/file/d/0BxPEJS0qVOpeWENSREI1RlNsNDQ/view?usp=sharing A hub is connected to a shaft with a shrink fit (pressurized oil assembly, grease removed). The material of the hub is quenched and tempered steel (ReH = 450 N/mm2) and the material of the shaft...

Ok after analyzing your past messages I came up with a new formula. a=(T/r-FL)⋅mη This considers Fwheel-road contact = Twheel shaft / rwheel radius, however T=moment of inertia x angular acceleration; how do i find the latter?

The question says on the driving shaft of the gear. I assume this means the point of the shaft between the wheels and motor-fan set-up. You are right, I made a mistake there, this should be the equation I meant Ms=(Jm+Jt)ηα-((D-d)/2)⋅FL and I think the shaft diameter does affect since the...

I had also delved around this thought, it does not make any sense... According to this you say and some calculations I managed to make last night, I came up with an equation, I hope it works for calculating the torque on the shaft once I find the angular acceleration: Ms=(Jm+Jt-((D-d)/2)⋅FL)ηα...