I think I'm getting lost in the numbers somewhere here.
Two astronauts, one of mass 60 kg and the other 84 kg, are initially at rest in outer space. They then push each other apart. How far apart are they when the lighter astronaut has moved 10 m?
m1= 60 kg
m2=84 kg
X initial = 0
X1...
1. A. A ball of mass 3.5 kg is thrown upward. It leaves the thrower's hand with a velocity of 12 m/s. The following questions refer to the motion after the ball leaves the thrower's hand. Assume that the upward direction is positive. Show all calculations.
a. How long does it take for the ball...
F = \frac {dp}{dt}
is that not the formula I used and got the incorrect answer
I though it should be -84/2.4 (change in momentum/change in time). -35 however is not correct.
Could you explain the other formula, I'm not sure what your trying to tell me. I'm not familiar with the squiggly...
Could someone help me out with this one, I can't seem to get on track here.
A ball of mass 3.5 kg is thrown upward. It leaves the thrower's hand with a velocity of 12 m/s. The ball is in the air for 2.4 seconds. Final velocity before the ball returns to the hand in -12 m/s. The change in...
acceleration is velocity squared over time
Speed would be 2 pi radius over time
4.08= v^2/1.10
4.08/1.1 = 3.71
Square root of 3.71 = 1.93
Would 1.93 then be the speed?
bucket of mass 1.80 kg is whirled in a vertical circle of radius 1.10 m. At the lowest point of its motion the tension in the rope supporting the bucket is 25.0 N.
Find the speed of the bucket.
f(t)-mg=mA
25-17.64=1.8 A
7.36 = 1. 8 A
A= 4.08
I'm told the answer above is incorrect...
Two crates, of mass m1 = 60 kg and m2 = 130 kg, are in contact and at rest on a horizontal surface (Fig. 4-54). A 620 N force is exerted on the 60 kg crate. The coefficient of kinetic friction is 0.15.
(a) Calculate the acceleration of the system.
m/s2 (to the right)
(b) Calculate the...
A ball hangs from a string on the rear view mirror of a car. The car is accelerating, causing the string to be at an angle theta with the vertical. If the car is accelerating at 1.0m/s2 and the mass of the ball is 4kg, what is the magnitude of the tension on the string, and at what angle is it...
Could someone remind me the proper way to solve this equation. I cannot recall how.
9.8 * Sin (theta) = 7.056 * Cos (theta)
Plugging number in and working backwads I got the answer theta=36 which is correct as far as I can tell.
A spring scale is stretched 10 cm when a force of 15 N is applied to it. How far apart should adjacent 1.0 N marks be on the scale?
Why would 1.5 cm not be correct?
Force= Spring Constant* Change in spring from rest
15n=k*10 cm
k=1.5