Recent content by rj3214

Yeah you're right it is with respect to the vertical so I would have to use cosine. Can I just solve part 3 for velocity and then set that equal to what the velocity was in part 1 and solve for θ that way?

I understand where you're going but how can you find the velocity of the ball right before it hits the block. This is what I got for part 1: mgsinθ = 1/2mv^2

The only formula's I can think of to use are energy conservation: 1/2mvf^2 + 1/2kxf^2 = 1/2mvi^2 + 1/2 kxi^2 mghf + 1/2kxf^2 = mghi + 1/2kxi^2

Homework Statement A 200 g rubber ball is tied to a 1.0 m long string and released from rest at angle θ. It swings down at the very bottom has a perfectly elastic collision with a 1.0 kg block. The block is resting on a frictionless surface and is connected to a horizontal 20 cm long spring of...