Thanks again for your time.
Yes, that's what I did as I thought when you were calculating the Thevenin's equivalent resistance you dropped the load (in this case the 5.5Ω)? Hence getting 4.5Ω.
Yes I get this.
Hmmm... OK.
Yup
What is (3/(3+6))? ((4Ω+2Ω)x6Ω)/(4Ω+2Ω+6)) /...
Cheers.
Can you elaborate on how I'm "way off" please? I had looked at the related topics earlier and the only one with anything useful (that I could see) had this:
In the second example I have calculated R[SIZE="1"]TH as being 4.5Ω
I[SIZE="1"]SC will be 10V/6Ω (the 9Ω resistor being...
Hello,
As part of a module of a HNC I'm looking at Thevenin's & Norton's Theorems. As it's distance learning and I work full-time it's easier for me to ask on here rather than contact the course lecturer - they're finished by the time I get home and I'm hoping I might get a response to my query...